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Given the structure definition in a 32-bit environment: struct contact { char name 22]; char gender; int phone; y malloc(sizeof(struct contact)); printf("%d\\", sizeof(y)); What value will be printed?

Option 1: 4
Option 2: 27
Option 3: 28
Option 4: 32

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User Shameen
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1 Answer

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Final answer:

The value that will be printed is 27.

Step-by-step explanation:

The given structure definition represents a contact with three fields: name, gender, and phone. The name field has a length of 22 characters, the gender field is a single character, and the phone field is an integer. In a 32-bit environment, each character occupies 1 byte and an integer occupies 4 bytes. Therefore, the total size of the structure is calculated as follows:

  1. 22 characters * 1 byte/character = 22 bytes
  2. 1 character * 1 byte/character = 1 byte
  3. 1 integer * 4 bytes/integer = 4 bytes

Adding up these sizes, we get a total of 22 bytes + 1 byte + 4 bytes = 27 bytes.

Hence, when the sizeof operator is used on an instance of this structure, it will return 27. Therefore, the value that will be printed is 27.

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User Zef
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