Question

How do I expand this

Answer 1

`cot^(4) x`

Explanation:

Answer 2

Explanation:

We have

`(sc^2x-1)^2`

Which is the same as

`(sc^2x-1)(sc^2x-1)`

To expand this polynomial, we can use the FOIL method. Meaning that we multiply the Fronts, Outsides, Insides, and Lasts together and then add each of these products.

The two fronts are
`sc^2x` and
`sc^2x`,

`(sc^2x )(sc^2x )=s^2c^4x^2`

The two Outsides are
`sc^2x` and
`-1`,

`(sc^2x )(-1)=-sc^2x`

The two Insides are
`-1` and
`sc^2x`,

`(-1)(sc^2x )=-sc^2x`

The two lasts are
`-1` and
`-1`,

`(-1)(-1)=1`

Now we just need to add these together to get

`s^2c^4x^2-sc^2x-sc^2x+1\\\\s^2c^4x^2-2sc^2x+1`