asked 183k views
0 votes
The value of the following Boolean expression is 1. (x + y)(T+ z), x = 1, y = 1, z = 0

a-True
b-False

1 Answer

1 vote

Final answer:

After substituting the provided values into the Boolean expression (x + y)(T+ z) and considering T as the Boolean constant true, the result is 2, not 1. Therefore, the statement is false.

Step-by-step explanation:

The question provided involves evaluating the value of a given Boolean expression by substituting the given values for x, y, and z. The expression is (x + y)(T+ z), with x, y, and z being equal to 1, 1, and 0, respectively. The question asks whether this expression evaluates to 1.

Firstly, we substitute the values into the expression as follows: (1 + 1)(T + 0). This simplifies to (2)T, since T is typically used to represent the Boolean constant true, which has a numerical equivalent of 1, the expression becomes 2*1, which is equal to 2.

Therefore, the value of the Boolean expression is 2, not 1. The given statement is false.

answered
User ORole
by
8.0k points

No related questions found