Question

Pls help me. To be submitted tomorrow​

Answer 1

`(1)/(7)`

Explanation:

Given

tanx =
`(3)/(4)` =
`(opposite)/(adjacent)`

This is a 3- 4- 5 right triangle with hypotenuse = 5, then

cosx =
`(adjacent)/(hypotenuse)` =
`(4)/(5)`

sinx =
`(opposite)/(hypotenuse)` =
`(3)/(5)`

Then

`(cosx-sinx)/(cosx+sinx)`

=
`((4)/(5)-(3)/(5) )/((4)/(5)+(3)/(5) )`

=
`((1)/(5) )/((7)/(5) )`

=
`(1)/(5)` ×
`(5)/(7)`

=
`(1)/(7)`