Final answer:
The ionic strength for a 0.0095 M solution of NaOH, which fully dissociates into Na+ and OH- ions, is calculated using the formula for ionic strength and is found to be 0.0095.
Step-by-step explanation:
To calculate the ionic strength of a solution, we use the formula:
I = 1/2 ∑ c_i z_i^2
where I represents the ionic strength, c_i is the molar concentration of each ion, and z_i is the charge number of that ion.
In the case of 0.0095 M NaOH, which fully dissociates into Na+ and OH- ions, both ions have a concentration of 0.0095 M and a charge of ±1, respectively. Applying the formula,
I = 1/2 [(0.0095)(1)^2 + (0.0095)(-1)^2] = 1/2 [0.0095 + 0.0095] = 0.0095.
Therefore, the ionic strength for the 0.0095 M NaOH solution is 0.0095.