Question

PLEASE HELP. give your answer accurate to 2 decimal places

Answer 1

`f(x)=\cfrac{-2x}{x+8} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{df}{dx}=\stackrel{ \textit{quotient rule} }{\cfrac{-2(x+8)-(-2x)(1)}{(x+8)^2}}\implies \cfrac{df}{dx}=\cfrac{-2x-16+2x}{(x+8)^2} \\\\\\ \left. \cfrac{df}{dx}=\cfrac{-16}{(x+8)^2} \right|_(x=8)\implies \cfrac{-16}{(8+8)^2}\implies -\cfrac{1}{16} ~~ \approx ~~ -0.06`