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4 votes
The product formed when Propyne was treated with NaNH2 followed

by treatment with Methyl lodide (2) and lastly the major product was
treated with (3) Lithium in Liquid ammonia is
(a) lodo propyne (b) 2-Butyne (c) 2-Butene (d) 1-Butyne

1 Answer

6 votes

Final answer:

The product formed when Propyne was treated with NaNH2 followed by treatment with Methyl iodide (2) and lastly the major product was treated with (3) Lithium in Liquid ammonia is 1-Butyne. Therefore, the correct option is (d) 1-Butyne.

Step-by-step explanation:

The product formed when Propyne was treated with NaNH2 followed by treatment with Methyl iodide (2) and lastly the major product was treated with (3) Lithium in Liquid ammonia is (d) 1-Butyne.

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