Question

How many ions are in 14.02 grams of cyanide

Answer 1

3.25x10²³ ions

Step-by-step explanation:

To solve this problem we'll first convert those 14.02 grams of cyanide (CN⁻) to moles, using its molar mass:

• 14.02 g ÷ 26 g/mol = 0.5392 mol

Then we'll convert those 0.5392 moles into number of ions, using Avogadro's number:

• 0.5392 mol * 6.023x10²³ ions/mol = 3.25x10²³ ions