Question

5. When a = 0, b=-1, find the value of the given expressions: (1) 2a + 2b (ii) 2a² + b² + 1 (iv) a² + ab +2... (iii) 2ab + 2ab² + ab​

Answer 1

Using the given values a = 0, b = -1, the evaluated expressions are -2, 2, 2, and 0, respectively.

Step-by-step explanation:

When given specific values for variables in algebraic expressions, you can find the value of these expressions by substituting the values for each variable. With a = 0 and b = -1, we can evaluate the following expressions:

• (i) 2a + 2b: This evaluates to 2(0) + 2(-1) = 0 - 2 = -2.
• (ii) 2a² + b² + 1: This evaluates to 2(0)² + (-1)² + 1 = 0 + 1 + 1 = 2.
• (iv) a² + ab + 2: This evaluates to (0)² + 0*(-1) + 2 = 0 + 0 + 2 = 2.
• (iii) 2ab + 2ab² + ab: This evaluates to 2(0)(-1) + 2(0)(-1)² + (0)(-1) = 0 + 0 + 0 = 0.

The values of the expressions with the given values for a and b are -2, 2, 2, and 0 respectively.