Question

for how many unique combinations of inputs does the boolean function 'f' evaluate to '1' (i.e., number of rows with f=1 in the truth table) if f(a,b,c,d,e) = ace ?

Answer 1

There are 32 unique combinations of inputs for which the boolean function 'f' evaluates to '1'.

Step-by-step explanation:

Number of unique combinations:

In this question, we have a boolean function 'f' defined as f(a,b,c,d,e)=ace. The function evaluates to '1' when a, c, and e are all '1', and b and d can be either '0' or '1'.

Based on this information, we can determine the number of unique combinations for which 'f' evaluates to '1' by considering the values of a, c, and e, and the two possibilities for b and d.

Since each variable can take two values (0 or 1), the total number of unique combinations is: 2 * 2 * 2 * 2 * 2 = 2^5 = 32.

Answer:

There are 32 unique combinations of inputs for which the boolean function 'f' evaluates to '1'.