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What is the pOH of a 5.7 × 10⁻⁴ M Sr(OH)2 solution?

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Final answer:

To calculate the pOH of a solution, multiply the concentration of the strong base by 2 and then take the negative logarithm.

Step-by-step explanation:

The pOH of a solution can be calculated using the following formula:

pOH = -log [OH-]

In the given question, we have a 5.7 × 10⁻⁴ M Sr(OH)2 solution. Since Sr(OH)2 is a strong base and dissociates completely, we can determine the concentration of hydroxide ions (OH-) in the solution by multiplying the concentration of Sr(OH)2 by 2. Thus, [OH-] = 2 x 5.7 × 10⁻⁴ M. Substituting this value into the formula, we can calculate the pOH.

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User Yomaris
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