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A child sets off the firecracker at a distance of 100 m from the family house. What is the sound intensity β100 at the house? Express the sound intensity in decibels.

1 Answer

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Final answer:

The sound intensity at a distance of 100 m from the source can be calculated using the inverse square law of sound propagation. Assuming the sound intensity of a single fly is 40.0 dB at a distance of 3.0 m, the sound intensity of 1000 flies at 100 m can be calculated as 70.0 dB.

Step-by-step explanation:

The sound intensity at a distance of 100 m from the source can be calculated using the inverse square law of sound propagation. According to this law, the sound intensity decreases with the square of the distance from the source.

Let's assume that the sound intensity at a distance of 3.0 m from a single fly is 40.0 dB. So, the sound intensity at a distance of 1000 flies, assuming no interference, can be calculated as:

Sound Intensity of 1000 flies = (Sound Intensity of a single fly) * 1000

Sound Intensity of 1000 flies = 40.0 dB + 10 * log10(1000)

Substituting the values:

Sound Intensity of 1000 flies = 40.0 dB + 10 * 3

Sound Intensity of 1000 flies = 40.0 dB + 30 dB

Sound Intensity of 1000 flies = 70.0 dB

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User Minho
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