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What is the mole fraction of I₂ in a solution made by dissolving 83.4 g of I₂ in 245 g of hexane, C₆H₁₄?

1 Answer

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Final answer:

The mole fraction of I2 in the solution is calculated to be 0.104 by dividing the moles of dissolved iodine (0.329) by the total moles of the mixture (3.172 moles).

Step-by-step explanation:

Calculating Mole Fraction of Iodine in Hexane

To calculate the mole fraction of I2 (iodine) when it is dissolved in hexane (C6H14), first, you need to calculate the number of moles of iodine and hexane. Use the molecular weight of I2, which is 253.8 g/mol to find the moles of iodine. For hexane, its molecular weight is 86.18 g/mol. Then, add the moles of iodine and hexane to determine the total moles in the solution. Finally, divide the moles of iodine by the total moles to obtain the mole fraction.

Calculating the moles of I2: 83.4 g I2 × (1 mol I2 / 253.8 g I2) = 0.329 moles I2

Calculating the moles of C6H14: 245 g C6H14 × (1 mol C6H14 / 86.18 g C6H14) = 2.843 moles C6H14

Calculating the total moles: 0.329 moles I2 + 2.843 moles C6H14 = 3.172 total moles

Calculating the mole fraction of I2: 0.329 moles I2 / 3.172 total moles = 0.104 (mole fraction of I2)

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User Jim Fred
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