Final answer:
Sodium hydroxide reacts with hydrofluoric acid to produce sodium fluoride and water. The balanced molecular equation is NaOH(aq) + HF(aq) → NaF(aq) + H2O(l). The net ionic equation, since Na+ is a spectator ion, is H+(aq) + OH-(aq) → H2O(l).
Step-by-step explanation:
When sodium hydroxide (NaOH), a strong base, reacts with hydrofluoric acid (HF), a weak acid, the reaction produces sodium fluoride (NaF) and water (H2O). Here are the balanced molecular, complete ionic, and net ionic equations for this acid-base reaction:
Balanced Molecular Equation:
NaOH(aq) + HF(aq) → NaF(aq) + H2O(l)
Total Ionic Equation:
Na+(aq) + OH−(aq) + H+(aq) + F−(aq) → Na+(aq) + F−(aq) + H2O(l)
Net Ionic Equation:
H+(aq) + OH−(aq) → H2O(l)
In this reaction, the sodium ion (Na+) is a spectator ion and does not participate in the reaction. The net ionic equation shows the reaction between the hydroxide ion (OH−) and the hydronium ion (H+), which are responsible for the neutralization that produces water.
The balanced molecular, total ionic, and net ionic equations for the reaction between sodium hydroxide (NaOH) and hydrofluoric acid (HF) are as follows:
Balanced Molecular Equation: NaOH(aq) + HF(aq) → NaF(aq) + H2O(l)
Total Ionic Equation: Na+(aq) + OH-(aq) + H+(aq) + F-(aq) → Na+(aq) + F-(aq) + H2O(l)
Net Ionic Equation: OH-(aq) + H+(aq) → H2O(l)