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a rod 4.16 m long is uniformly charged and has a total charge of 4.62 μc. determine the magnitude of the total electric field (unit in n/c) along the axis of the rod at a point 7.14 m from its center.

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User Cilap
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1 Answer

4 votes

Final answer:

To determine the magnitude of the total electric field along the axis of the rod at a point 7.14 m from its center, we can use the principle of superposition.

Step-by-step explanation:

To determine the magnitude of the total electric field along the axis of the rod at a point 7.14 m from its center, we can use the principle of superposition. The electric field due to a uniformly charged rod at a point along its axis can be calculated using the formula:

E = (k * Q * L)/(2 * pi * r * (r^2 + (L/2)^2)^(3/2))

Where E is the electric field, k is the Coulomb's constant (9 * 10^9 N.m^2/C^2), Q is the total charge on the rod (4.62 * 10^-6 C), L is the length of the rod (4.16 m), and r is the distance from the center of the rod (7.14 m).

By substituting the given values into the equation, we can calculate the magnitude of the total electric field.

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User AGrush
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7.9k points
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