Question

If a projectile is launched from an initial height of 35 ft with an initial upward velocity of 60 ft per second, what is the maximum height reached by the projectile?

1) 45 ft
2) 55 ft
3) 65 ft
4) 75 ft

Answer 1

Using the kinematic equations for projectile motion, we can calculate that the maximum height reached by a projectile with an initial upward velocity of 60 ft/s from a height of 35 ft is approximately 90.9 ft, which is not reflected in the provided options.

Step-by-step explanation:

To determine the maximum height reached by a projectile, we need to consider the effects of gravity on the projectile's initial vertical velocity. Given the initial upward velocity of 60 ft per second and an initial height of 35 ft, we can use the kinematic equations for projectile motion to find the maximum height. The formula to find the maximum height (h) when the initial velocity (v0) and gravitational acceleration (g) are known is:

h = h0 + (v0^2) / (2g) where h0 is the initial height.

Since the acceleration due to gravity (g) is 32.2 ft/s2, and taking up as positive, we can calculate:

h = 35 ft + (60 ft/s)^2 / (2 * 32.2 ft/s2)

h = 35 ft + 3600 ft2/s2 / 64.4 ft/s2

h = 35 ft + 55.9 ft

h = 90.9 ft

The maximum height reached by the projectile is approximately 90.9 ft, which indicates that the given options might not be accurate, or the question might have been interpreted incorrectly.