Question

The number of surface flaws in plastic panels used in the interior of automobiles follows a Poisson distribution with a mean of 0.02. What is the probability of having exactly 3 surface flaws?

Answer 1

The probability of having exactly 3 surface flaws in plastic panels used in the interior of automobiles can be calculated using the Poisson distribution formula.

Step-by-step explanation:

To find the probability of having exactly 3 surface flaws in plastic panels used in the interior of automobiles, we can use the Poisson distribution formula. The mean of the Poisson distribution is given as 0.02. The probability mass function for the Poisson distribution is given by:

P(X = x) = (e-λ * λx) / x!

where λ is the mean of the distribution and x is the desired number of surface flaws. Plugging in the values, we have:

P(X = 3) = (e-0.02 * 0.023) / 3! = (e-0.02 * 0.000008) / 6 ≈ 0.00000427