Final answer:
The charge on each plate of a parallel-plate capacitor is ±1.412 × 10^-21 C.
Step-by-step explanation:
The charge on each plate of a parallel-plate capacitor can be found using the formula:
Q = CV
Where Q is the charge on each plate, C is the capacitance, and V is the voltage applied. In this case, the charge on each plate is ±0.706 nC, and the capacitance can be calculated using the formula:
C = ε₀A/d
Where ε₀ is the permittivity of free space, A is the area of each plate, and d is the distance between the plates. By rearranging the formula, we can solve for the charge on each plate:
Q = C × V
Inserting the given values:
Q = (2.0 pF) × (0.706 nC)
Converting the values to proper units:
1 pF = 10-12 F
1 nC = 10-9 C
Q = (2.0 × 10-12 F) × (0.706 × 10-9 C)
Simplifying the expression:
Q = 1.412 × 10-21 C
Therefore, the charge on each plate is approximately ±1.412 × 10-21 C.