Question

At 25°C, k = 0.090 for the following reaction: H₂O(g) + Cl2O(g) ⇌ 2 HOCl(g). Calculate the concentrations of all species at equilibrium for each of the following cases?

Answer 1

To calculate the concentrations at equilibrium for the reaction H₂O(g) + Cl2O(g) ⇌ 2 HOCl(g) at 25°C with a Kc of 0.090, set up an ICE table and calculate the changes in concentration.

Step-by-step explanation:

At 25°C, the reaction H₂O(g) + Cl2O(g) ⇌ 2 HOCl(g) has an equilibrium constant (Kc) of 0.090. To calculate the concentrations at equilibrium, we can set up an ICE table to track the changes in concentration.

Let x be the change in concentration for both H₂O and Cl₂O. The initial concentrations are [H₂O] = 1.00 M and [Cl₂O] = 1.00 M.

In the ICE table, the change in concentration for HOCl will be 2x since the stoichiometric coefficient is 2. The equilibrium concentrations can then be calculated by adding the changes to the initial concentrations.