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Given [H₃O+] = 3.5×10⁻⁹ m, calculate [OH⁻]?

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Final answer:

The hydroxide ion concentration ([OH-]) is calculated using the ion product constant of water (Kw) and the given hydronium ion concentration ([H3O+]). By substituting the given values into the formula [OH-] = Kw / [H3O+], we find that the [OH-] is 2.857x10^-6 M.

Step-by-step explanation:

To calculate the hydroxide ion concentration ([OH⁻]) given the hydronium ion concentration ([H₃O⁺] = 3.5×10⁻⁹ M), we use the ion product constant for water (Kw) at 25°C, which is 1.0×10⁻¹⁴.

The relationship between the concentrations of [H₃O⁺] and [OH⁻] is given by the expression:
Kw = [H₃O⁺][OH⁻]

Rearranging the formula to solve for [OH⁻], we get:
[OH⁻] = Kw / [H₃O⁺]

Substituting the given value:
[OH⁻] = 1.0×10⁻¹⁴ / (3.5×10⁻⁹) = 2.857×10⁻⁶ M

Thus, the concentration of hydroxide ions in the solution is 2.857×10⁻⁶ M.

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