Final answer:
The current at point a (7 A) is the sum of the currents through R1 and R3, making it greater than the current at point b (5 A).
Step-by-step explanation:
Based on the information provided, we can conclude that the current at point a must be the sum of the currents flowing through resistors R1 and R3. Since the current through R1 is 5 A and through R3 is 2 A, the total current at point a would be 7 A (5 A + 2 A). The current at point b would just be the current flowing through resistor R1, which is given as 5 A. Therefore, the current at point b is 5 A, which is less than at point a. In terms of the resistor i1 (assumed to be R1 based on context), its current is given to be 5 A, which is equal to the current at point b but less than the current at point a. Concerning the provided statements, we know that the current at point a is not greater than at point b, as the current at a includes both currents from R1 and R3, and hence the current at a (7 A) is greater than at b (5 A). Consequently, option 1 is false. Options 2 and 4 are suggesting the same relationship (though option 4 does not consider the superposition at point a), and neither of them is claiming that the current at b is greater than at a. Option 3 is not provided in the question, but if we were to evaluate it, we would say that the current through i1 (5 A) is not greater than the currents at points a (7 A) or b (5 A). Based on the provided descriptions of the currents, the true statement is that the current at point a is equal to the sum of the currents through R1 and R3, which is greater than the current at point b.