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Find the length of the curve r(t) = 6t, t², 19t³, 0 ≤ t ≤ 1?

1 Answer

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Final answer:

To find the length of the parametric curve r(t) = (6t, t², 19t³), we use the arc length formula, integrate the square root of the sum of the squares of the derivatives of each component of r(t), from t=0 to t=1.

Step-by-step explanation:

Finding the Length of the Curve

To find the length of the curve r(t) = (6t, t², 19t³) from t = 0 to t = 1, we use the formula for the arc length of a parametric curve in three dimensions, which is:


L = ∫_0^1 √((dx/dt)² + (dy/dt)² + (dz/dt)² ) dt

Taking the derivatives of each component of the position vector r(t), we find:

  • dx/dt = d/dt (6t) = 6
  • dy/dt = d/dt (t²) = 2t
  • dz/dt = d/dt (19t³) = 57t²

Substituting these derivatives into the arc length formula, we get:


L = ∫_0^1 √(6² + (2t)² + (57t²)² ) dt

Integrating this expression from t=0 to t=1 will give us the total arc length of the curve.

answered
User Steven Stark
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