Question

An electron has an initial velocity of 4.8 × 10⁶ m/s in a uniform 2.25 × 10⁵ N/C electric field. The field accelerates the electron in the direction opposite to its initial velocity. What is the acceleration experienced by the electron?

1) 1.08 × 10¹¹ m/s²
2) 2.16 × 10¹¹ m/s²
3) 4.32 × 10¹¹ m/s²
4) 8.64 × 10¹¹ m/s²

Answer 1

The acceleration experienced by the electron is approximately -3.95 × 10¹⁶ m/s².

The correct answer is none of all.

Step-by-step explanation:

To calculate the acceleration experienced by the electron, we can use Newton's second law, which states that force equals mass multiplied by acceleration. In this case, the force is given by the electric field strength multiplied by the charge of the electron, which is -1.60 × 10-19 C. So, the force can be calculated as:

Force = electric field strength × charge of the electron

Plugging in the values:

Force = (2.25 × 10⁵ N/C) × (-1.60 × 10-19 C)

Simplifying the multiplication:

Force = -3.6 × 10-14 N

Now, we can use Newton's second law to solve for acceleration. Rearrange the formula:

Acceleration = Force / mass

Plugging in the values:

Acceleration = (-3.6 × 10-14 N) / (9.11 × 10-31 kg)

Simplifying the division:

Acceleration = -3.95 × 10¹⁶ m/s²

So, the acceleration experienced by the electron is approximately -3.95 × 10¹⁶ m/s².