Question

For a normal distribution with μ = 100 and σ = 10, what percentage of scores have values less than x = 85?

Answer 1

To find the percentage of scores that have values less than 85 in a normal distribution with a mean (μ) of 100 and standard deviation (σ) of 10, calculate the Z-score and use Z-tables or a calculator to find the percentage.

Step-by-step explanation:

To find the percentage of scores that have values less than 85 in a normal distribution with a mean (μ) of 100 and standard deviation (σ) of 10, we can use the Z-score formula.

The Z-score is calculated as Z = (X - μ) / σ, where X is the score we want to find the percentage for.

In this case, the Z-score is Z = (85 - 100) / 10 = -1.5.

From Z-tables or using a calculator, we can find that the area to the left of Z = -1.5 is approximately 0.0668 or 6.68%. Therefore, approximately 6.68% of scores have values less than 85.