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a missle was fired from a submarine from 330 feet below sea level. if the missile reached a height of 7600 feet before exploding, what was the change in the altitude of the missile

asked
User Kirugan
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9.0k points

1 Answer

5 votes

Final answer:

The change in altitude of the missile is calculated by subtracting the initial depth below sea level from the final height above sea level, resulting in a total change of 7930 feet.

Step-by-step explanation:

You asked about the change in altitude of a missile fired from a submarine that was 330 feet below sea level and reached a height of 7600 feet before exploding. To find the change in altitude, we calculate the difference between the final height and the initial depth. The initial depth is 330 feet below sea level, which we treat as a negative altitude, and the final height above sea level is 7600 feet.

We calculate the change in altitude as follows:
Change in altitude = Final height above sea level - Initial depth below sea level
Change in altitude = 7600 feet - (-330 feet)
Change in altitude = 7600 feet + 330 feet
Change in altitude = 7930 feet

So, the missile changed altitude by a total of 7930 feet from the time it was launched until it exploded.

answered
User Damianodamiano
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8.3k points
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