Question

If an investment account starts with $3,900, and grows with 2.1% interest, compounded annually, how much is the account worth after 15 years?

Round your answer to the nearest dollar.
Do NOT round until you have calculated the final answer.

Answer 5327

Answer 1

Answer: 5327

Explanation:

Use the formula for calculating compound interest

A(t)=P(1+rn)n⋅t,

where A(t) is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), n is the number of times the interest is compounded each year, and t is the time (in years). We are given that P=$3,900, r=0.021, n=1, and t=15. Substituting the values into the formula and using a calculator to evaluate, we find

A(t)=P(1+rn)n⋅t=$3,900(1+0.0211)(15)(1)≈$5,326.61

So the final answer is $5,327.

Answer 2

$5327

Explanation:

Use the formula for calculating compound interest

A(t)=P(1+r/n)^n⋅t,

where A(t) is the balance of the account, P is the principal, r is the annual interest rate (as a decimal), n is the number of times the interest is compounded each year, and t is the time (in years). We are given that P=$3,900, r=0.021, n=1, and t=15. Substituting the values into the formula and using a calculator to evaluate, we find

A(t)=P(1+r/n)^n⋅t = $3,900(1+0.0211)^(15)(1) ≈ $5,326.61

So the final answer is $5,327.