Final answer:
The hydroxide ion concentration ([OH-]) for a 0.013 M solution of Sr(OH)2 is 0.026 M because each mole of Sr(OH)2 produces two moles of OH- ions upon full dissociation.
Step-by-step explanation:
To find the hydroxide ion concentration ([OH−]) for a 0.013 M solution of Sr(OH)2, we need to understand that strontium hydroxide is a strong base and fully dissociates in water. The dissociation can be represented as follows:
Sr(OH)2 → Sr2+ + 2OH−
Since each mole of Sr(OH)2 produces two moles of OH− ions, we must multiply the initial concentration of the Sr(OH)2 solution by 2:
[OH−] = 2 * 0.013 M = 0.026 M
Therefore, the hydroxide ion concentration ([OH−]) for a 0.013 M solution of Sr(OH)2 is 0.026 M.