Question

A gas with a volume of 3 times 10 to the second ml at 150 degree celsisus is heated until its volume expands to 6 times 10 to the second ml. What is the new temperature of the gas if the pressure remains constant during the heating process?

Answer 1

The new temperature of the gas is 846 K, which is equivalent to 573°C (846 K - 273).

Step-by-step explanation:

The student is asking about the relationship between the volume and temperature of a gas. This is an application of Charles's law, which states that, at a constant pressure, the volume of a gas is directly proportional to its temperature on an absolute scale (Kelvin). The initial volume (V1) is 300 ml (3 times 10 to the second ml) at an initial temperature (T1) of 150°C, which is 423 K (150 + 273). The final volume (V2) is 600 ml (6 times 10 to the second ml).

Using Charles's law formula, V1/T1 = V2/T2, and solving for T2 gives:

T2 = (V2 × T1) / V1 = (600 ml × 423 K) / 300 ml = 846 K.

Therefore, the new temperature of the gas is 846 K, which is equivalent to 573°C (846 K - 273).