Final answer:
The mass of products formed when a solution containing 2.00g of Hg(NO3)2 is added to a solution of Na2S is 1.44 grams of HgS.
Step-by-step explanation:
To calculate the mass of products formed when a solution containing 2.00g of Hg(NO3)2 is added to a solution of Na2S, we need to first determine the balanced chemical equation for the reaction between these two compounds. Since mercury(II) nitrate reacts with sodium sulfide to form mercury(II) sulfide and sodium nitrate, the balanced equation is:
Hg(NO3)2(aq) + Na2S(aq) → HgS(s) + 2NaNO3(aq)
From the balanced equation, we can see that 1 mole of Hg(NO3)2 reacts with 1 mole of Na2S to produce 1 mole of HgS. The molar mass of HgS is 232.67 g/mol. Therefore, the mass of HgS formed can be calculated as:
2.00g Hg(NO3)2 * (1 mol Hg(NO3)2/ 324.605 g) * (1 mol HgS / 1 mol Hg(NO3)2) * (232.67 g/ 1 mol HgS) = 1.44 g HgS
So, the mass of products formed in this reaction is 1.44 grams of HgS.