Question

Exercise 2: A balanced dime is tossed twice. The four possible equally likely

outcomes are {HH, HT, TH, TT}. Let
A = event the first toss is heads,
B = event the second toss is heads, and
C = event at least one toss is heads.
Determine the following probabilities
P(B)
P(B|A)
P(B |C)
P(C)
P(CIA)
P(C|(not B)

Answer 1

P(B) = 1/2

P(B|A) = 1/4

P(B|C) = 1/2

P(C) = 3/4

P(C|A) = 1/2

P(C|not B) = 1/4