Question

a technician adds 0.025 l of 200 mm buffer stock solution to a volumetric flask and dilutes the stock to 1.0 l. what is the final concentration of the solution

Answer 1

The final concentration of the buffer solution after dilution to 1.0 L is 5 millimolar (mM).

Step-by-step explanation:

When a technician adds 0.025 liters (L) of a 200 millimolar (mM) buffer stock solution to a volumetric flask and dilutes it to 1.0 liter (L), we can calculate the final concentration of the solution using the dilution equation, C1V1 = C2V2, where C1 and C2 represent the concentrations of the stock and final solutions.

Respectively, and V1 and V2 represent their volumes. The final concentration (C2) can be calculated by rearranging the equation to solve for C2: C2 = (C1V1) / V2. Substituting the given values (C1 = 200 mM or 0.200 M, V1 = 0.025 L, and V2 = 1.0 L), we get C2 = (0.200 M × 0.025 L) / 1.0 L = 0.005 M. Therefore, the final concentration of the buffer solution after dilution is 5 millimolar (mM).