Question

the radius r and height h of a circular cone change at a rate of 2 cm/min. the height of the cone is twice the radius. how fast is the volume of the cone changing when the radius is 10 cm?

Answer 1

V = (1/3)πr²(2r) = (2/3)πr³

dV/dt = 2πr²(dr/dt)

= 2π(10 cm)²(2 cm/min)

= 400π cm³/min