Final answer:
The mass of 9.45 mol of aluminum oxide (Al₂O₃) is calculated by multiplying the molar mass of Al₂O₃ (101.96 g/mol) with 9.45 mol, which gives us 964 g, corresponding to answer choice C.
Step-by-step explanation:
The student has asked me to calculate the mass of 9.45 mol of aluminum oxide (Al₂O₃). To find the mass, we need to calculate the molar mass of Al₂O₃ and multiply it by the number of moles given, which is 9.45 mol.
Knowing that the molar mass of aluminum (Al) is 26.98 g/mol and that of oxygen (O) is 16 g/mol, we calculate the molar mass of Al₂O₃ as follows:
(2 × 26.98 g/mol) + (3 × 16 g/mol) = 53.96 g/mol + 48 g/mol = 101.96 g/mol.
Now, to find the mass of 9.45 mol of Al₂O₃:
9.45 mol × 101.96 g/mol = 964.02 g
Therefore, rounding to three significant figures, the mass of 9.45 mol of aluminum oxide is 964 g, which corresponds to answer choice C.