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For the function f(x)=x²−8, determine the slope of the secant line between x=−2 and x=6.

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Final answer:

The slope of the secant line for the function f(x) = x² - 8 between x = -2 and x = 6 is calculated by finding the y-values at these points and using the slope formula. It results in a slope of 4.

Step-by-step explanation:

To determine the slope of the secant line between two points on the function f(x) = x² - 8, you need to calculate the difference in the y-values of the function at these two x-values, divided by the difference in the x-values. This is also known as the rise over run formula.

First, we need to find the y-values for x = -2 and x = 6. Substituting these x-values into the function gives us:

  • f(-2) = (-2)² - 8 = 4 - 8 = -4
  • f(6) = (6)² - 8 = 36 - 8 = 28

Now we have two points: Point 1 (-2, -4) and Point 2 (6, 28).

Next, we calculate the slope using the formula:

Slope (Δy/Δx) = (y2 - y1) / (x2 - x1)

Slope = (28 - (-4)) / (6 - (-2))

Slope = 32 / 8

Slope = 4

Therefore, the slope of the secant line between x = -2 and x = 6 for the function f(x) = x² - 8 is 4.

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User Tymik
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