Question

A greyhound weighing 45 kg is being anesthetized with Acepromazine at a dosage of 1mg/kg. If the concentration is 5 mg/mL, how many mL should be given?

Answer 1

The greyhound should be given 9 mL of Acepromazine, calculated by dividing the total required dosage in milligrams (45 mg) by the concentration in mg/mL (5 mg/mL).

Step-by-step explanation:

To calculate how many milliliters (mL) of Acepromazine should be administered to a greyhound weighing 45 kg at a dosage of 1 mg/kg, when the concentration of Acepromazine is 5 mg/mL, we need to first calculate the total milligrams of drug needed for the dog's weight:

• Total dosage in mg = weight in kg × dosage per kg = 45 kg × 1 mg/kg = 45 mg.

Next, we find out how many mL contain the required dosage, given the concentration:

• Number of mL needed = Total dosage in mg ÷ concentration in mg/mL = 45 mg ÷ 5 mg/mL = 9 mL.

Therefore, the greyhound should be given 9 mL of Acepromazine.