asked 6.2k views
5 votes
What does the following code do?

for (int i = 1; i < cboNumbers.Items.Count; i += 2){
cboNumbers.Items[i] = "XXX";
}
a. It changes the first item in the combo box to "XXX".
b. It changes every second item in the combo box to "XXX".
c. It changes every item in the combo box to "XXX".
d. It doesn't change any items in the combo box.

asked
User Nivox
by
8.1k points

1 Answer

4 votes

Final answer:

The code changes every second item in the combo box to "XXX". The change starts with the second item (index 1) and affects only odd-indexed items (which are even-numbered positions).

Step-by-step explanation:

The provided code snippet is iterating over the items in a combo box with the identifier cboNumbers. The for loop starts at index 1 (which is the second item in the combo box, as indexing starts from 0) and increments the index by 2 in each iteration. This means that the loop will change every second item in the combo box to the string "XXX".

To be more specific, the loop impacts the items at indices 1, 3, 5, and so on, up until the last index that is less than cboNumbers.Items.Count, which is the count of items in the combo box. Since it skips every other item, only the odd-indexed items (which are actually the even-numbered items if you start counting from 1) are affected.

answered
User Jbaums
by
8.3k points
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