Question

I am so confused with this question.

Answer 1

C

Explanation:

I don't know if there's an easier way to do it but here's the way I did it:
(x+3)^4= (x^2+6x+9)^2

(x^2+6x+9)^2=x^4+12x^3+54x^2+108x+81

108 is C, and the largest value.

I just got the full equation and saw which one was the biggest.

Answer 2

c) 108

Explanation:

To rewrite
`\sf f(x) = (x+3)^4` in the form
`\sf f(x) = x^4 + ax^3 + bx^2 + cx + d`, we need to expand the expression. The expanded form will help us identify the coefficients
`\sf a, b, c,` and
`\sf d`.

`\sf f(x) = (x+3)^4`

Expand using the binomial theorem or other methods:

`\sf f(x) = x^4 + 4x^3 \cdot 3 + 6x^2 \cdot 3^2 + 4x \cdot 3^3 + 3^4`

`\sf f(x) = x^4 + 12x^3 + 54x^2 + 108x + 81`

Now, we can compare the coefficients:

`\sf a = 12, \quad b = 54, \quad c = 108, \quad d = 81`

Now, to determine which of
`\sf a, b, c,` or
`\sf d` is the greatest, compare their values:

`\sf a = 12, \quad b = 54, \quad c = 108, \quad d = 81`

In this case,
`\sf c = 108` is the greatest value among
`\sf a, b, c,` and
`\sf d`. Therefore, the correct answer is
`\sf c`.