Question

1 loop in the primary coil and 8 loops in the secondary. If the secondary voltage is 120 V, what must be the primary voltage

Answer 1

`V_(p) = 15 V`

Step-by-step explanation:

Given the following data;

Number of loops in primary coil, Np = 1 loop.

Number of loops in secondary coil, Ns = 8 loops

Voltage in secondary coil, Vs = 120V

To find the voltage in the primary coil, Vp;

Transformer ratio is given by the formula;

`(V_(p))/(V_(s)) = (N_(p))/(N_(s))`

Making Vp the subject of formula;

`V_(p) = (N_(p))/(N_(s)) * V_(s)`

Substituting into the equation, we have;

`V_(p) = (1)/(8) * 120`

`V_(p) = (120)/(8)`

`V_(p) = 15 V`

Therefore, the voltage in the primary coil, Vp is 15 Volts.