Question

What is the change in enthalpy in joules when 5.44 x 10^-4 mol of AgCl dissolves in water according to the following chemical equation: AgCl (s) → Ag⁺ (aq) + Cl⁻ (aq) ΔH = 65.5 kJ

A. 35434 J
B. 35680 J
C. 35680 kJ
D. 35434 kJ

Answer 1

The change in enthalpy when 5.44 x 10^-4 mol of AgCl dissolves in water is approximately 35,634 J (joules), which corresponds to option A.

Step-by-step explanation:

The question involves calculating the change in enthalpy when a given amount of AgCl dissolves in water. If the enthalpy change for the dissolution of 1 mole of AgCl is 65.5 kJ, then for the dissolution of 5.44 x 10^-4 moles of AgCl, the enthalpy change in joules can be found by multiplying these two values.

To find the enthalpy change in joules (J), you would use the conversion factor that 1 kJ = 1000 J. Therefore, the enthalpy change for 5.44 x 10^-4 moles would be:

65.5 kJ/mol x 5.44 x 10^-4 mol x 1000 J/kJ

After doing the math, you find that the enthalpy change is approximately 35,634 J, which corresponds to option A.