Question

Calculate the resistance of the bulb when a 60-watt light bulb operates at a voltage of 120 V.

a) 2 Ω
b) 30 Ω
c) 240 Ω
d) 72 Ω
e) 7,200 Ω

Answer 1

To calculate the resistance of the bulb, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). The resistance of the bulb is 240 Ω.

Step-by-step explanation:

To calculate the resistance of the bulb, we can use Ohm's Law, which states that resistance (R) is equal to voltage (V) divided by current (I). The power (P) of the bulb is given as 60 watts, and the voltage is 120 volts. We can use the formula P = IV, where I is the current. Rearranging the formula, we have I = P / V. Substituting the given values, we get I = 60 / 120 = 0.5 Amps. Now, using Ohm's Law, R = V / I = 120 / 0.5 = 240 Ω. Therefore, the resistance of the bulb is 240 Ω.