asked 92.9k views
2 votes
Give the general solution of dy/dx=2xy²-2x+3y²-3

asked
User Slowwie
by
8.4k points

1 Answer

6 votes

Final answer:

To find the general solution of the differential equation dy/dx = 2xy² - 2x + 3y² - 3, we can use the method of separating variables and integrate both sides to find the general solution.

Step-by-step explanation:

To find the general solution of the differential equation dy/dx = 2xy² - 2x + 3y² - 3, we can use the method of separating variables.

  1. Move all terms containing dy to one side of the equation: dy/(3y² - 2y) = (2x - 3)dx.
  2. Separate the variables by multiplying both sides by dx and dividing both sides by (3y² - 2y): (1/(3y² - 2y))dy = (2x - 3)dx.
  3. Integrate both sides with respect to their respective variables: ∫(1/(3y² - 2y))dy = ∫(2x - 3)dx.
  4. Solve the integrals to find the general solution.

The integration will involve techniques such as partial fractions and u-substitution, which should be done step by step and may lead to different forms of the solution depending on the values of the constants involved.

answered
User KaroluS
by
7.9k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.