Question

Consider the following series: [infinity] n 4 n2 n = 1. What is the value of the series?

1) 0
2) 1
3) [infinity]
4) None of the above

Answer 1

The value of the series is 2n^2.

Step-by-step explanation:

The given series is infinity n 4 n^2 n = 1.

To find the value of the series, we can observe that the expression in the box is equal to n^2. By rearranging and grouping terms, we can rewrite the series as:

2[n + 3 + ....+(2n − 3)+n]

Now, we can simplify the expression to:

2n^2

Therefore, the value of the series is 2n^2.