Final answer:
The power dissipated in the 3 ohm resistor is 1.08 W.
Step-by-step explanation:
The power dissipated in the 3 ohm resistor can be calculated using Joule's law, P = IV, where P is electric power. In this case, each resistor has the same full current flowing through it. By substituting Ohm's law V = IR into Joule's law, we can find the power dissipated by the first resistor as:
P₁ = I²R₁ = (0.600 A)²(3 Ω) = 1.08 W