Question

The sum of three even integers is -108. find the three integers

Answer 1

To find three even integers whose sum is -108, we can use the equation: x + (x + 2) + (x + 4) = -108. Simplifying the equation, we get: 3x + 6 = -108. Dividing both sides by 3, we get: x = -38. So the three even integers are -38, -36, and -34.

Step-by-step explanation:

To find three even integers whose sum is -108, we can use the equation:

x + (x + 2) + (x + 4) = -108

Simplifying the equation, we get:

3x + 6 = -108

Subtracting 6 from both sides, we have:

3x = -114

Dividing both sides by 3, we get:

x = -38

So the three even integers are -38, -36, and -34.