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If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR?

If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR?
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If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR?

If K is the midpoint of ER, EK = x + 5, and ER = 4x + 2, what is the length of KR-example-1
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User Mayur
by
8.4k points

1 Answer

4 votes

Answer:

Explanation:

EK = ½ER

x+5 = ½(4x+2)

x+5 = 2x+1

x=4

answered
User Vasiliy
by
8.7k points
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