Question

Given that Avogadro's number is 6.02 x 1023 particles (atoms, molecules, etc) per mole. How many atoms are there in 0.500 mole of zinc?

A. 1.20 x 1024 atoms
B. 0.500 x 1023 atoms
C. 131 atoms
D. 3.01 x 1023 atoms
E. 33 atoms
F. 6.02 x 1023 atoms

Answer 1

B. 0.500 x 1023 atoms. To find the number of atoms in 0.500 mole of zinc, we multiply the number of moles by Avogadro's number. Therefore, there are 3.01 x 10^23 atoms in 0.500 mole of zinc.

Step-by-step explanation:

To determine the number of atoms in 0.500 mole of zinc, we can use Avogadro's number, which is 6.02 x 1023 particles per mole. Since zinc is an element, we can assume that the particles refer to atoms.

To find the number of atoms, we multiply the number of moles by Avogadro's number:

Number of atoms = 0.500 mole x 6.02 x 1023 atoms/mole = 3.01 x 1023 atoms

Therefore, there are 3.01 x 1023 atoms in 0.500 mole of zinc. The correct answer is option D.