Question

. A lot consisting of 50 bulbs is inspected by taking at random 10 bulbs and testing them. If the number of defective bulbs out of 10 is 0, then lot is accepted; otherwise it is rejected. If there are 2 defective bulbs in the lot, what is the probability of accepting the lot?

Answer 1

The probability of accepting the lot when there are 2 defective bulbs is 0.7374, or approximately 73.74%.

Step-by-step explanation:

In order to find the probability of accepting the lot when there are 2 defective bulbs, we need to calculate the probability of having 0 defective bulbs out of 10 given that there are 2 defective bulbs in the lot.

Using the binomial distribution, we can calculate this probability as follows:

P(X = 0) = (50 choose 0) * (0.03)^0 * (0.97)^(10-0)

= (1) * (1) * (0.97)^10

= 0.7374

Therefore, the probability of accepting the lot when there are 2 defective bulbs is 0.7374, or approximately 73.74%.