Final answer:
When three identical bulbs of 60W, 200V rating are connected in series to a 200V supply, the power drawn by them will be C. 20 watt.
Step-by-step explanation:
When three identical bulbs of 60W, 200V rating are connected in series to a 200V supply, the power drawn by them will be C. 20 watt. In a series circuit, the total resistance is equal to the sum of individual resistances.
Since the bulbs are connected in series, the voltage across each bulb will be 200V/3 = 66.67V.
The power drawn by each bulb can be calculated using the formula
P = V^2/R,
where P is the power, V is the voltage, and R is the resistance.
Since the voltage across each bulb is 66.67V and the power rating is 60W, we can rearrange the formula to solve for resistance:
R = V^2/P.
Plugging in the values,
R = (66.67V)^2 / 60W = 74.08 ohms.
Therefore, the power drawn by each bulb in a series circuit is given by
P = V^2 / R
= (66.67V)^2 / 74.08 ohms = 60W.