asked 195k views
0 votes
Consider a mass-spring system. The spring has a constant k = 8 N/m and the mass m = 5 kg. The mass oscillates with an amplitude of 7 cm and follows the equations of motion in the introduction. What is the period of oscillation of the mass-spring system?

1) 2�� seconds
2) �� seconds
3) ��/2 seconds
4) 2 seconds

1 Answer

4 votes

Final answer:

The period of oscillation for the given mass-spring system with a spring constant of 8 N/m and a mass of 5 kg is approximately 2π seconds, which is close to 6.28 seconds.

The correct option is option 1.

Step-by-step explanation:

The student is asking about the period of oscillation for a mass-spring system. To find the period of a mass-spring oscillator, we use the formula T = 2π√(m/k), where T is the period in seconds, m is the mass in kilograms, and k is the spring constant in Newtons per meter.

Given that the spring constant k is 8 N/m and the mass m is 5 kg, we can plug these values into the formula to find the period:

T = 2π√(5 kg / 8 N/m) = 2π√(0.625) ≈ 2π√(0.625) ≈ 2π(0.79) ≈ 2π seconds, which is approximately 6.28 seconds. So the correct answer is option 1.

The correct option is option 1.

answered
User Bruh
by
7.9k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.