Final answer:
The net ionic equation for the reaction between Lead II Nitrate and sodium hydroxide is Pb²⁺ (aq) + 2 OH⁻ (aq) → Pb(OH)₂ (s), where lead(II) nitrate reacts with sodium hydroxide to form solid lead(II) hydroxide, and the sodium and nitrate ions are spectator ions.
Step-by-step explanation:
The net ionic equation for the reaction between Lead II Nitrate and sodium hydroxide is as follows:
Pb(NO₃)₂ (aq) + 2 NaOH (aq) → Pb(OH)₂ (s) + 2 NaNO₃ (aq)
Net Ionic Equation: Pb²⁺ (aq) + 2 OH⁻ (aq) → Pb(OH)₂ (s)
In the reaction, lead(II) nitrate and sodium hydroxide react to form solid lead(II) hydroxide as the precipitate.
The sodium ions (Na⁺) and nitrate ions (NO₃⁻) are spectator ions and are not included in the net ionic equation since they do not change in the course of the reaction.